18x^2+60x=90

Solution for 18x^2+60x=90 equation:

18x^2+60x=90

We move all terms to the left:

18x^2+60x-(90)=0

a = 18; b = 60; c = -90;
Δ = b2-4ac
Δ = 602-4·18·(-90)
Δ = 10080
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10080}=\sqrt{144*70}=\sqrt{144}*\sqrt{70}=12\sqrt{70}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-12\sqrt{70}}{2*18}=\frac{-60-12\sqrt{70}}{36}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+12\sqrt{70}}{2*18}=\frac{-60+12\sqrt{70}}{36}
$